y^2+0.05y-1=0

Solution for y^2+0.05y-1=0 equation:

y^2+0.05y-1=0

a = 1; b = 0.05; c = -1;
Δ = b2-4ac
Δ = 0.052-4·1·(-1)
Δ = 4.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.05)-\sqrt{4.0025}}{2*1}=\frac{-0.05-\sqrt{4.0025}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.05)+\sqrt{4.0025}}{2*1}=\frac{-0.05+\sqrt{4.0025}}{2}
$